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x^2-6x-952=0
a = 1; b = -6; c = -952;
Δ = b2-4ac
Δ = -62-4·1·(-952)
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-62}{2*1}=\frac{-56}{2} =-28 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+62}{2*1}=\frac{68}{2} =34 $
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